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Chapter NotesClass 11, JEE, NEET

Chemical Bonding: Explained With Examples (Class 11)

Ionic, covalent and coordinate bonds, Lewis structures, VSEPR shapes, hybridisation and molecular orbital theory for Class 11 — each with the examples examiners use and the rules for predicting shape.

17 September 2026·4 min read·7Solve Team

Atoms bond to reach a lower-energy arrangement — usually a full outer shell. Class 11 asks four things: which kind of bond forms, what shape the molecule takes, what orbitals are involved, and why some molecules are paramagnetic. Each has a rule you can apply in under a minute.

Kinds of bond

Fajan's rules predict covalent character in an "ionic" compound: a small, highly charged cation and a large anion polarise strongly. So LiI is more covalent than LiF; AlCl₃ is more covalent than NaCl.

Lewis structures and formal charge

Count valence electrons, place the least electronegative atom at the centre (never H), connect with single bonds, distribute the remaining electrons to satisfy octets, and make multiple bonds if the centre is short.

Formal charge = valence electrons − non-bonding electrons − ½(bonding electrons). The best structure has formal charges closest to zero. In CO₂ the structure O=C=O has all zeros; O≡C–O does not.

Octet exceptions: BF₃ (6 electrons on B), PCl₅ and SF₆ (expanded octet), NO and NO₂ (odd electron).

VSEPR — predicting shape

Electron pairs around the central atom repel and spread out as far as possible. Count bond pairs + lone pairs; lone pairs repel more, so they squeeze the bond angles.

DomainsLone pairsShapeExampleAngle
20LinearBeCl₂, CO₂180°
30Trigonal planarBF₃120°
31BentSO₂<120°
40TetrahedralCH₄109.5°
41Trigonal pyramidalNH₃107°
42BentH₂O104.5°
50Trigonal bipyramidalPCl₅120°, 90°
51See-sawSF₄
52T-shapedClF₃
53LinearXeF₂180°
60OctahedralSF₆90°
61Square pyramidalBrF₅
62Square planarXeF₄90°

Repulsion order: lone pair–lone pair > lone pair–bond pair > bond pair–bond pair. That is why the angle drops from 109.5° (CH₄) to 107° (NH₃) to 104.5° (H₂O).

Hybridisation — which orbitals

The number of electron domains gives the hybridisation directly:

Bonds: a single bond is one σ; a double bond is σ + π; a triple bond is σ + 2π. In ethene each carbon is sp²; the C=C has one σ (sp²–sp²) and one π (p–p). In ethyne each carbon is sp with two π bonds.

Shortcut for the steric number: (valence electrons of central atom + number of monovalent atoms attached ± charge)/2. For NH₃: (5 + 3)/2 = 4 → sp³. For NH₄⁺: (5 + 4 − 1)/2 = 4 → sp³.

Molecular orbital theory — why O₂ is paramagnetic

Atomic orbitals combine into bonding (lower energy) and antibonding (higher, marked *) molecular orbitals. Fill them in order, and:

Bond order = (bonding electrons − antibonding electrons)/2.

Order for O₂, F₂: σ1s, σ1s, σ2s, σ2s, σ2p_z, π2p_x = π2p_y, π2p_x = π2p_y, σ*2p_z. Order for B₂, C₂, N₂ (and lighter): the π2p pair lies below σ2p_z.

Hydrogen bonding

An H attached to N, O or F attracts a lone pair on another N, O or F. It explains why water boils at 100 °C while H₂S is a gas, why ice floats (open lattice), and why o-nitrophenol is more volatile than p-nitrophenol (intramolecular vs intermolecular H-bonding).

How it is tested

Frequently asked questions

What is the difference between sigma and pi bonds?

A sigma bond forms by head-on overlap along the bond axis and is stronger; a pi bond forms by sideways overlap of p orbitals above and below the axis and is weaker. A single bond is one sigma; a double bond is one sigma plus one pi.

How do I find the hybridisation of a molecule quickly?

Count the electron domains around the central atom (bonded atoms plus lone pairs). 2 = sp, 3 = sp², 4 = sp³, 5 = sp³d, 6 = sp³d².

Why is water bent and not linear?

Oxygen has four electron domains (two bonds, two lone pairs), so the electron geometry is tetrahedral; the two lone pairs push the O–H bonds closer, giving a bent shape with a 104.5° angle.

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